测试环境:
win10 x86-64
gcc: x86_64-pc-cygwin
1. 说明
1)作为函数形参时(也只有这种情况),数组与指针等同,int *p = int a[],p和a在函数内部都是指针
2)数组作为函数形参时将被转化为指向数组第一个元素的指针,无论是int a[10]还是int a[]形式的形参,在函数内部都是int *a形式指针
3)没有办法直接将数组本身传递给函数(可以间接传递,如将数组封装再结构体内~~~)
3)由于规则2),下列用法均正确,it's amazing!
fun(&i);
fun(p);
fun(a);
2. 代码:
#include <stdio.h>#include <stdlib.h>void fun(int a[10]){printf("fun: a[0] = %d\n", *a);}void fun2(int a[]){printf("fun2: a[0] = %d\n", *a);}void fun3(int *a){printf("fun2: a[0] = %d\n", *a);}int main(){int i = 1;int *p = NULL;int a[10] = {5};p = &i;fun(&i);fun(p);fun(a);fun2(&i);fun2(p);fun2(a);fun3(&i);fun3(p);fun3(a);return 0;}
3. 编译
无warning无error
4. 运行
D:\baoli\Desktopλ .\a.exefun: a[0] = 1fun: a[0] = 1fun: a[0] = 5fun2: a[0] = 1fun2: a[0] = 1fun2: a[0] = 5fun2: a[0] = 1fun2: a[0] = 1fun2: a[0] = 5