直接上示例代码
import restrs='''</li><li class="new-search-works-item"><a title="高考宣传海报" href="/show/34840284.html"target="_blank" class="search-works-thumb relative"><img src="/pic/0331/3680455_171255068085_4.jpg" alt="高考宣传海报"></a><div class="search-works-info"><a href="/show/34840284.html" class="search-works-name ellipsis" title="高考宣传海报">高考宣传海报</a><span class="search-works-price">非商售价：<span>38</span></span></div></li><li class="new-search-works-item"><a title="高考加油校园励志海报" href="/show/34843187.html"target="_blank" class="search-works-thumb relative"><img src="/pic/0401/24611550_080435886108_4.jpg" alt="高考加油校园励志海报"></a><div class="search-works-info"><a href="/show/34843187.html" class="search-works-name ellipsis" title="高考加油校园励志海报">高考加油校园励志海报</a><span class="search-works-price">非商售价：<span>40</span></span></div></li>'''strs=re.findall('img src="(.*?)"', strs,re.S)print(strs)
如上一段html代码，是我随便找了个图片网站复制的，现在是要取出源码中的两个jpg图片的链接，使用正则re.S轻松搞定，而且输出结果为列表
['/pic/0331/3680455_171255068085_4.jpg', '/pic/0401/24611550_080435886108_4.jpg']
正则中，(.*?) 正则匹配的是图片链接，img src=" 是图片链接前面的字符，" 是链接后面的字符。
