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python实现高级计算器_高级计算器功能Tkinter GUI和variab

时间:2023-05-31 17:34:36

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python实现高级计算器_高级计算器功能Tkinter GUI和variab

编辑:我修正了这个帖子所涉及的错误,等等,现在我正在尝试一种不同的方式来实现我最初想要的高级功能。这次我有一个显示器,还有一个显示功能。按钮通过在所述显示中插入文本来调用更新功能。我想知道如何使用这个函数,也许textvariable =这样我就可以把我的按钮文本从1,2,3,4改成。。。9,0到A,B,C,D…I,J。我的代码在下面,任何帮助都将不胜感激。:)from tkinter import *

import time

root = Tk()

root.title('Calculator')

displayb = Entry(root)

displayb.grid(row = 1, columnspan = 6)

mode = 0

i = 0

'''def update():

global mode

if mode == 0:

mode = 1

else:

mode = 0

return'''

def display(e):

global i

displayb.insert(i,e)

i += 1

txt1 = StringVar()

a = '1' if mode == 0 else 'A'

one = Button(root, text = '1', command = lambda : display(1))

txt1.set(a)

one.grid(row = 2, column = 0)

two = Button(root, text = '2', command = lambda : display(2))

two.grid(row = 2, column = 1)

three = Button(root, text = '3', command = lambda : display(3))

three.grid(row = 2, column = 2)

four = Button(root, text = '4', command = lambda : display(4))

four.grid(row = 3, column = 0)

five = Button(root, text = '5', command = lambda : display(5))

five.grid(row = 3, column = 1)

six = Button(root, text = '6', command = lambda : display(6))

six.grid(row = 3, column = 2)

seven = Button(root, text = '7', command = lambda : display(7))

seven.grid(row = 4, column = 0)

eight = Button(root, text = '8', command = lambda : display(8))

eight.grid(row = 4, column = 1)

nine = Button(root, text = '9', command = lambda : display(9))

nine.grid(row = 4, column = 2)

zero = Button(root, text = '0', command = lambda : display(0))

zero.grid(row = 5, column = 1)

'''shift = Button(root, text = 'sft', command = lambda : mode = 1 if mode == 0 else 0)

shift.grid(row = 2, column = 1)'''

root.mainloop()

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