Latex语法

1 花体字母2 常用数学符号3 常用数学字母4 矩阵的表示5 连加和连乘6 Latex公式的格式设置6.1 换行对齐6.2 公式带编号

1 花体字母

$\mathbb{R}$$\mathcal{R}$$\mathscr{R}$

效果分别是

A,R,S,P\mathbb{A} ,\mathbb{R}, \mathbb{S}, \mathbb{P}A,R,S,P

A,R,S,P\mathcal{A},\mathcal{R}, \mathcal{S}, \mathcal{P}A,R,S,P

A,R,S,P\mathscr{A},\mathscr{R},\mathscr{S},\mathscr{P}A,R,S,P

2 常用数学符号

3 常用数学字母

4 矩阵的表示

参见/qq_38228254/article/details/79469727

5 连加和连乘

\sum_{i=1}^{n}效果：

∑i=1n\sum_{i=1}^{n}i=1∑n​

\prod_{i=1}^{n}效果：

∏i=1n\prod_{i=1}^{n}i=1∏n​

其中

_后面加的是下标，^后面加的是上标

6 Latex公式的格式设置

6.1 换行对齐

$$ \begin{aligned}V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\&G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\&G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9\end{aligned}$$

效果：

Vπ(s)=Gt1⋅P(a1)⋅p1+Gt2⋅P(a1)⋅p2+Gt3⋅P(a1)⋅p3+Gt4⋅P(a2)⋅p4+Gt5⋅P(a2)⋅p5+Gt6⋅P(a2)⋅p6+Gt7⋅P(a3)⋅p7+Gt8⋅P(a3)⋅p8+Gt9⋅P(a3)⋅p9\begin{aligned} V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\ &G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\ &G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9 \end{aligned} Vπ​(s)=​Gt1​⋅P(a1​)⋅p1​+Gt2​⋅P(a1​)⋅p2​+Gt3​⋅P(a1​)⋅p3​+Gt4​⋅P(a2​)⋅p4​+Gt5​⋅P(a2​)⋅p5​+Gt6​⋅P(a2​)⋅p6​+Gt7​⋅P(a3​)⋅p7​+Gt8​⋅P(a3​)⋅p8​+Gt9​⋅P(a3​)⋅p9​​

备注：&在哪，就在哪里对齐。

6.2 公式带编号

\tag{编号}编号有括号

$$ \begin{aligned}V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\&G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\&G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9 \tag{1-1}\end{aligned}$$

Vπ(s)=Gt1⋅P(a1)⋅p1+Gt2⋅P(a1)⋅p2+Gt3⋅P(a1)⋅p3+Gt4⋅P(a2)⋅p4+Gt5⋅P(a2)⋅p5+Gt6⋅P(a2)⋅p6+Gt7⋅P(a3)⋅p7+Gt8⋅P(a3)⋅p8+Gt9⋅P(a3)⋅p9(1-1)\begin{aligned} V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\ &G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\ &G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9 \tag{1-1} \end{aligned} Vπ​(s)=​Gt1​⋅P(a1​)⋅p1​+Gt2​⋅P(a1​)⋅p2​+Gt3​⋅P(a1​)⋅p3​+Gt4​⋅P(a2​)⋅p4​+Gt5​⋅P(a2​)⋅p5​+Gt6​⋅P(a2​)⋅p6​+Gt7​⋅P(a3​)⋅p7​+Gt8​⋅P(a3​)⋅p8​+Gt9​⋅P(a3​)⋅p9​​(1-1)

\tag*{编号}编号无括号

$$ \begin{aligned}V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\&G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\&G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9 \tag*{1-1}\end{aligned}$$

Vπ(s)=Gt1⋅P(a1)⋅p1+Gt2⋅P(a1)⋅p2+Gt3⋅P(a1)⋅p3+Gt4⋅P(a2)⋅p4+Gt5⋅P(a2)⋅p5+Gt6⋅P(a2)⋅p6+Gt7⋅P(a3)⋅p7+Gt8⋅P(a3)⋅p8+Gt9⋅P(a3)⋅p91-1\begin{aligned} V_\pi(s)=&G_{t1}·P(a_1)·p_1+G_{t2}·P(a_1)·p_2+G_{t3}·P(a_1)·p_3+\\ &G_{t4}·P(a_2)·p_4+G_{t5}·P(a_2)·p_5+G_{t6}·P(a_2)·p_6+\\ &G_{t7}·P(a_3)·p_7+G_{t8}·P(a_3)·p_8+G_{t9}·P(a_3)·p_9 \tag*{1-1} \end{aligned} Vπ​(s)=​Gt1​⋅P(a1​)⋅p1​+Gt2​⋅P(a1​)⋅p2​+Gt3​⋅P(a1​)⋅p3​+Gt4​⋅P(a2​)⋅p4​+Gt5​⋅P(a2​)⋅p5​+Gt6​⋅P(a2​)⋅p6​+Gt7​⋅P(a3​)⋅p7​+Gt8​⋅P(a3​)⋅p8​+Gt9​⋅P(a3​)⋅p9​​1-1