问题补充:
设F为抛物线y2=2px(p>0)的焦点,A、B、C为该抛物线上三点,当FA+FB+FC
答案:
设向量FA FB FC分别为(x1,y1)(x2,y2)(x3,y3) 则x1+x2+x3=0
|FA|+|FB|+|Fc|=3
XA=x1+p2
时间:2019-03-13 17:54:50
设F为抛物线y2=2px(p>0)的焦点,A、B、C为该抛物线上三点,当FA+FB+FC
设向量FA FB FC分别为(x1,y1)(x2,y2)(x3,y3) 则x1+x2+x3=0
|FA|+|FB|+|Fc|=3
XA=x1+p2